If ∠BAC = 17° and ∠CED = 17° are the two triangles, ΔBAC and ΔCED similar? If so, by what criterion?A) yes, by AA similarity criterion B) yes, by SAS similarity criterion C) yes, by SSA similarity criterion D) no, not possible to tell.

No, not possible to tell that the the two triangles, ΔBAC and ΔCEDare similar ⇒ answer DStep-by-step explanation:Let us revise the cases of similarity1. AAA similarity : two triangles are similar if all three angles in the first   triangle equal the corresponding angle in the second triangle  2. AA similarity : If two angles of one triangle are equal to the    corresponding angles of the other triangle, then the two triangles      are similar.3. SSS similarity : If the corresponding sides of the two triangles are    proportional, then the two triangles are similar.4. SAS similarity : In two triangles, if two sets of corresponding sides      are proportional and the included angles are equal then the two      triangles are similar.In the two triangles BAC and CED∵ m∠BAC = 17°∵ m∠CED = 17°∴ m∠BAC = m∠CED But we need another pair of angles to prove that the two triangles aresimilar by AA similarity criterionOR The lengths of sides BA , CA and CE , DE to show that [tex]\frac{BA}{CE}=\frac{CA}{DE}[/tex] = constant ratio and prove that the two triangles are similar by SAS similarity criterionSo it is not possible to prove that the two triangles are similarNo, not possible to tell that the the two triangles, ΔBAC and ΔCEDare similarLearn more:You can learn more about triangles in brainly.com/question/4354581#LearnwithBrainly