A recently negotiated union contract allows workers in a shipping department 24 minutes for rest, 10 minutes for personal time, and 14 minutes for delays for each four hours worked. A time study analyst observed a job that is performed continuously and found an average time of 6.0 minutes per cycle for a worker she rated at 95 percent. What standard time is applicable for that operation? (Do not round intermediate calculations. Round your final answer to 3 decimal places.)

Answer:7.125 minStep-by-step explanation:GivenResting time =24 minPersonal time=10 minDelay=14 minObserved Time=6min/cyclePerformance Rating=95%Allowance Time=Rest time+Personal time+delayAllowance time=24+10+14=48 min[tex]Allowance %=\frac{Allowance Time}{Total Time}=\frac{48}{4\times 60}=20 \%[/tex]Allowance Factor=[tex]\frac{1}{1-0.20}=\frac{5}{4}[/tex]Calculate the Normal TimeNormal time=Observed time[tex]\times [/tex]personal Time=6\times 0.95=5.7 minStandard time=Normal time [tex]\times[/tex] Allowance FactorStandard time =[tex]NT\times Allowance factor=5.7\times 1.25[/tex]=7.125 min